y=(1/x)^2

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Solution for y=(1/x)^2 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

y = (1/x)^2 // - (1/x)^2

y-(1/x)^2 = 0

-1*x^-2 = -y // : -1

x^-2 = y

-2 < 0

1/(x^2) = y // * x^2

1 = x^2*y // : y

1/y = x^2

x^2 = 1/y // ^ 1/2

abs(x) = 1/(y^(1/2))

x = 1/(y^(1/2)) or x = -(1/(y^(1/2)))

x in { 1/(y^(1/2)), -(1/(y^(1/2))) }

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